x^2-6x-9-49=0

Solution for x^2-6x-9-49=0 equation:

x^2-6x-9-49=0

We add all the numbers together, and all the variables

x^2-6x-58=0

a = 1; b = -6; c = -58;
Δ = b2-4ac
Δ = -62-4·1·(-58)
Δ = 268
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{268}=\sqrt{4*67}=\sqrt{4}*\sqrt{67}=2\sqrt{67}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{67}}{2*1}=\frac{6-2\sqrt{67}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{67}}{2*1}=\frac{6+2\sqrt{67}}{2}
$